In this figure, area of ∆ AFB is equal to the area of parallelogram ABCD.
If altitude EF is 16 cm long, find the altitude of the parallelogram to
the base AB of length 10cm. What is the area of ∆DAO, where O is
the mid point of DC? Hint: Area of triangle = 1/2*base*height. Area of parallelogram = base*height