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12.1 A Goniometrische vergelijkingen
12.1 A Goniometrische vergelijkingen
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Slide 1:
Slide
wiskunde
Middelbare school
vwo
Leerjaar 5
This lesson contains
14 slides
, with
interactive quiz
and
text slides
.
Lesson duration is:
45 min
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Items in this lesson
12.1 A Goniometrische vergelijkingen
Slide 1 - Slide
Welke vergelijking is (zonder omschrijven) algebraïsch op te lossen?
A
sin
(
x
)
=
−
sin
(
2
x
)
B
cos
(
x
)
=
sin
(
2
x
)
C
cos
(
−
2
x
)
=
cos
(
x
+
π
)
D
(
sin
(
x
)
)
2
=
sin
(
x
)
+
2
Slide 2 - Quiz
Slide 3 - Slide
Slide 4 - Slide
Bekende rekenregels
Slide 5 - Slide
sin
(
x
)
=
sin
(
−
2
x
)
Slide 6 - Slide
sin
(
x
)
=
sin
(
−
2
x
)
x
=
−
2
x
+
k
⋅
2
π
∨
x
=
π
+
2
x
+
k
⋅
2
π
Slide 7 - Slide
sin
(
x
)
=
sin
(
−
2
x
)
x
=
−
2
x
+
k
⋅
2
π
∨
x
=
π
+
2
x
+
k
⋅
2
π
3
x
=
k
⋅
2
π
∨
−
x
=
π
+
k
⋅
2
π
Slide 8 - Slide
sin
(
x
)
=
sin
(
−
2
x
)
x
=
−
2
x
+
k
⋅
2
π
∨
x
=
π
+
2
x
+
k
⋅
2
π
3
x
=
k
⋅
2
π
∨
−
x
=
π
+
k
⋅
2
π
x
=
k
⋅
3
2
π
∨
x
=
π
+
k
⋅
2
π
Slide 9 - Slide
cos
(
x
)
=
sin
(
2
x
)
Slide 10 - Slide
cos
(
x
)
=
sin
(
2
x
)
cos
(
x
)
=
cos
(
2
x
−
2
1
π
)
Slide 11 - Slide
cos
(
x
)
=
sin
(
2
x
)
cos
(
x
)
=
cos
(
2
x
−
2
1
π
)
x
=
2
x
−
2
1
π
+
k
⋅
2
π
∨
x
=
−
2
x
+
2
1
π
+
k
⋅
2
π
Slide 12 - Slide
cos
(
x
)
=
sin
(
2
x
)
cos
(
x
)
=
cos
(
2
x
−
2
1
π
)
x
=
2
x
−
2
1
π
+
k
⋅
2
π
∨
x
=
−
2
x
+
2
1
π
+
k
⋅
2
π
−
x
=
−
2
1
π
+
k
⋅
2
π
∨
3
x
=
2
1
π
+
k
⋅
2
π
Slide 13 - Slide
cos
(
x
)
=
sin
(
2
x
)
cos
(
x
)
=
cos
(
2
x
−
2
1
π
)
x
=
2
x
−
2
1
π
+
k
⋅
2
π
∨
x
=
−
2
x
+
2
1
π
+
k
⋅
2
π
−
x
=
−
2
1
π
+
k
⋅
2
π
∨
3
x
=
2
1
π
+
k
⋅
2
π
x
=
2
1
π
+
k
⋅
2
π
∨
x
=
6
1
π
+
k
⋅
3
2
π
Slide 14 - Slide
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