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7.3 A factorising trinomials
Invoegen plattegrond op niveau
1 / 17
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Slide 1:
Slide
Wiskunde
Middelbare school
havo
Leerjaar 2
This lesson contains
17 slides
, with
interactive quizzes
and
text slides
.
Lesson duration is:
50 min
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Items in this lesson
Invoegen plattegrond op niveau
Slide 1 - Slide
Invoegen plattegrond op niveau
Slide 2 - Slide
Today
You are able to factorise trinomials using the product-sum method.
Slide 3 - Slide
Find two numbers of which the product is 15 and the sum 8.
Slide 4 - Open question
Find two numbers of which the product is -20 and the sum 8.
Slide 5 - Open question
Expand the brackets:
(
x
+
2
)
(
x
+
7
)
Slide 6 - Open question
We've just seen that
Can you find a relation between 2, 7 and 9, 14?
This relation is always there.
We can use this relation to factorise trinomials.
(
x
+
2
)
(
x
+
7
)
=
x
2
+
9
x
+
1
4
Slide 7 - Slide
To factorise
we need two numbers which give +30 when multiplied and +13 when added.
Which two numbers do we need?
There's always just one solution.
x
2
+
1
3
x
+
3
0
Slide 8 - Slide
To factorise
we need two numbers which give +30 when multiplied and +13 when added.
It's 3 and 10, so
x
2
+
1
3
x
+
3
0
x
2
+
1
3
x
+
3
0
=
(
x
+
3
)
(
x
+
1
0
)
Slide 9 - Slide
Three more examples:
x
2
−
5
x
−
5
0
x
2
+
x
−
6
x
2
+
3
x
−
4
Slide 10 - Slide
Three more examples:
x
2
−
5
x
−
5
0
x
2
+
x
−
6
x
2
+
3
x
−
4
=
(
x
+
4
)
(
x
−
1
)
Slide 11 - Slide
Three more examples:
x
2
−
5
x
−
5
0
x
2
+
x
−
6
=
(
x
+
3
)
(
x
−
2
)
x
2
+
3
x
−
4
=
(
x
+
4
)
(
x
−
1
)
Slide 12 - Slide
Three more examples:
x
2
−
5
x
−
5
0
=
(
x
−
1
0
)
(
x
+
5
)
x
2
+
x
−
6
=
(
x
+
3
)
(
x
−
2
)
x
2
+
3
x
−
4
=
(
x
+
4
)
(
x
−
1
)
Slide 13 - Slide
Factorise:
x
2
+
6
x
−
2
7
A
(x + 3)(x + 9)
B
(x - 9)(x + 3)
C
(x - 3)(x + 9)
D
(x + 9)(x - 3)
Slide 14 - Quiz
Factorise:
x
2
+
1
1
x
+
1
0
Slide 15 - Open question
Factorise:
x
2
+
2
x
+
1
Slide 16 - Open question
Slide 17 - Slide
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