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Chapter 8.2
Chapter 8.2
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Chapter 8.2
Slide 1 - Diapositive
Period 2
Sound
Slide 2 - Diapositive
This lesson
Recap
Paragraph 8.2 — pitch and frequency
Working independently
Slide 3 - Diapositive
How is sound produced?
Through a vibration
What is sound made off?
Sound waves
How does sound travel over distance?
Through a medium
Slide 4 - Diapositive
Pitch is a word we use to describe how high or low a sound is. For example:
– A whistle has a high pitch.
– A drum has a low pitch.
The pitch of the sound depends on in a string instrument:
1.Thickness: the thinner the string, the higher the pitch
the thicker the string, the lower the pitch
2.Length: the shorter the string, the higher the pitch
3.Tension: the tighter the string, the higher the pitch"
Slide 5 - Diapositive
We can make sound visible. We do this with an oscilloscope.
With the oscilloscope you can analyze the sound.
Slide 6 - Diapositive
The screen of the oscilloscope is divided into small squares. The time base tells you how much time one square represents.
For example: A time base of 500 ms/division means that one square shows 500 milliseconds."
Slide 7 - Diapositive
The vibration period and frequency
Each square on the oscilloscope gives an amount of time called
Time base
time base = 0,5 ms per
division
And each vibration takes a certain
amount of time to complete
Slide 8 - Diapositive
The vibration period and frequency
The vibration period is the amount of time it takes to complete 1 full vibration
In this picture we see multiple vibrations, at which point(s) do we see a completed vibration?
Slide 9 - Diapositive
The vibration period and frequency
With the time 1 square takes up, and the amount of completed vibrations we can calculte the vibration period (T)
For example, we have
3 completed vibrations
What is the time for these 3 vibrations?
Slide 10 - Diapositive
The vibration period and frequency
We divide the time it takes to complete a certain amount of vibrations with the number of vibrations and we get the vibration period (T)
T = 2,4/3=0,8ms = 0,0008 s
So one full vibration = 0,0008 s
Slide 11 - Diapositive
The vibration period and frequency
If we know the period of a vibration we can calculate its frequency (f) in Hertz (Hz)
We can use this the formula
f = 1/T
If we know the frequency and want to
Calculate vibration period: then you can
Use T= 1/f
Slide 12 - Diapositive
The vibration period and frequency
When we calculated T we got the answer of 0,8ms
Now we can calculate the frequency
f = 1/t
f=1/0,0008=1250Hz
Which means 1250 vibrations per second
Slide 13 - Diapositive
The vibration period and frequency
We humans are able to hear sounds with low and high frequencies
Our hearing range is between 20hz and 20000hz
Slide 14 - Diapositive
Slide 15 - Diapositive
See the images below. total time is 8 milliseconds go by.
What is the frequency of this wave? use the formula
f
=
T
1
Slide 16 - Diapositive
See the images below. you have 1 ms/div.
What is the frequency of this wave? use the formula
f
=
T
1
Given
T = 2 milliseconds = 0.002 seconds.
Asked
What is the frequency?
Formula
Calculation
f = 1/T = 1/0.002 =500 Hz
f
=
T
1
Slide 17 - Diapositive
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