Differentiëren - 5A

Wat is de afgeleide van

f(x) = 2x

f'(x) = 2x

f'(x) = 2

f'(x) = 0

f'(x) = 1

1 / 10

Slide 1: Quiz

WiskundeMiddelbare schoolvwoLeerjaar 5

This lesson contains 10 slides, with interactive quizzes.

Lesson duration is: 50 min

Items in this lesson

Wat is de afgeleide van

f(x) = 2x

f'(x) = 2x

f'(x) = 2

f'(x) = 0

f'(x) = 1

Slide 1 - Quiz

Wat is de afgeleide van

f (x) = x^{​ 2 ​ ​}

f'(x) = 2x

f'(x) = 2

f'(x) = 0

f'(x) = 1

Slide 2 - Quiz

De afgeleide van

is

f (x) = x^{​ 2 ​ ​} + 3 x

f'(x) = 2x

f'(x) = x + 3

f'(x) = 3x + 2

f'(x) = 2x + 3

Slide 3 - Quiz

De afgeleide van

is

f (x) = - 4 x^{​ 3 ​ ​} + 3

f^{​' ​ ​} (x) = - 12 x^{​ 2 ​ ​}

f^{​' ​ ​} (x) = - 12 x + 3

f^{​' ​ ​} (x) = - 4 x^{​ 2 ​ ​} + 3

f^{​' ​ ​} (x) = - 9 x^{​ 3 ​ ​}

Slide 4 - Quiz

Wat is de afgeleide van

f (x) = x^{​ 3 ​ ​} + 5 x^{​ 2 ​ ​} + 4 x + 8

f^{​' ​ ​} (x) = x^{​ 2 ​ ​} + x + 4

f^{​' ​ ​} (x) = 3 x^{​ 2 ​ ​} + 10 x + 4 + 8

f^{​' ​ ​} (x) = 3 x^{​ 3 ​ ​} + 10 x + x

f^{​' ​ ​} (x) = 3 x^{​ 2 ​ ​} + 10 x + 4

Slide 5 - Quiz

Gegeven is

Bereken de afgeleide.

y = 6 \sqrt ​ x ​ ​ ​ + \frac{​ 4 ​ ​}{​ x ​}

\frac{​ d y ​ ​}{​ d x ​} = \frac{​ 6 ​ ​}{​ \sqrt ​ x ​ ​ ​ ​} - \frac{​ 4 ​ ​}{​ x ​}

\frac{​ d y ​ ​}{​ d x ​} = \frac{​ 3 ​ ​}{​ \sqrt ​ x ​ ​ ​ ​} - \frac{​ 4 ​ ​}{​ x ^{​ 2 ​ ​} ​}

\frac{​ d y ​ ​}{​ d x ​} = \frac{​ 3 ​ ​}{​ \sqrt ​ x ​ ​ ​ ​} + 4

\frac{​ d y ​ ​}{​ d x ​} = \frac{​ 3 ​ ​}{​ \sqrt ​ x ​ ​ ​ ​} + \frac{​ 4 ​ ​}{​ x ^{​ 2 ​ ​} ​}

Slide 6 - Quiz

Differentieer de volgende functie:

f (x) = \frac{​ 3 ​ ​}{​ x ^{​ 6 ​ ​} ​} + \frac{​ 1 ​ ​}{​ 2 x ^{​ 2 ​ ​} ​}

f^{​' ​ ​} (x) = \frac{​ 3 ​ ​}{​ 6 x ^{​ 5 ​ ​} ​} + \frac{​ 1 ​ ​}{​ 4 x ​}

f^{​' ​ ​} (x) = - \frac{​ 1 8 ​ ​}{​ x ^{​ 7 ​ ​} ​} - \frac{​ 1 ​ ​}{​ x ^{​ 3 ​ ​} ​}

f^{​' ​ ​} (x) = \frac{​ 1 ​ ​}{​ 2 x ^{​ 5 ​ ​} ​} + \frac{​ 1 ​ ​}{​ 4 x ​}

f^{​' ​ ​} (x) = 18 x^{​ 5 ​ ​} + x

Slide 7 - Quiz

Wat is de afgeleide?

f (x) = x^{​ 3 ​ ​} \sqrt ​ x ​ ​ ​

f^{​' ​ ​} (x) = 3 x^{​ 3 \frac{​ 1 ​ ​}{​ 2 ​} ​ ​}

f^{​' ​ ​} (x) = 3 \frac{​ 1 ​ ​}{​ 2 ​} x^{​ 2 ​ ​} \sqrt ​ x ​ ​ ​

f^{​' ​ ​} (x) = \frac{​ 1 ​ ​}{​ 2 ​} x^{​ 2 \frac{​ 1 ​ ​}{​ 2 ​} ​ ​}

f^{​' ​ ​} (x) = \frac{​ 7 ​ ​}{​ 2 ​} x^{​ \frac{​ 5 ​ ​}{​ 2 ​} ​ ​}

Slide 8 - Quiz

Wat is de afgeleide van

f (x) = (x^{​ 3 ​ ​} + 2)^{​ 4 ​ ​}

f^{​' ​ ​} (x) = 4 (x^{​ 3 ​ ​} + 2)^{​ 3 ​ ​}

f^{​' ​ ​} (x) = 12 x^{​ 11 ​ ​}

f^{​' ​ ​} (x) = 12 x^{​ 2 ​ ​} (x^{​ 3 ​ ​} + 2)^{​ 3 ​ ​}

f^{​' ​ ​} (x) = 4 (3 x^{​ 2 ​ ​} + 2)^{​ 3 ​ ​}

Slide 9 - Quiz

Wat is de afgeleide?

f (x) = \sqrt ​ 4 x^{​ 4 ​ ​} + 2 x^{​ 2 ​ ​} ​ ​ ​

f^{​' ​ ​} (x) = \sqrt ​ 16 x^{​ 3 ​ ​} + 4 x ​ ​ ​

f^{​' ​ ​} (x) = \frac{​ 1 6 x ^{​ 3 ​ ​} + 4 x ​ ​}{​ \sqrt ​ 4 x ^{​ 4 ​ ​} + 2 x ^{​ 2 ​ ​} ​ ​ ​ ​}

f^{​' ​ ​} (x) = \frac{​ 8 x ^{​ 3 ​ ​} + 2 x ​ ​}{​ \sqrt ​ 4 x ^{​ 4 ​ ​} + 2 x ^{​ 2 ​ ​} ​ ​ ​ ​}

f^{​' ​ ​} (x) = \frac{​ 1 6 x ^{​ 3 ​ ​} + 4 x ​ ​}{​ 2 \sqrt ​ 4 x ^{​ 4 ​ ​} + 2 x ^{​ 2 ​ ​} ​ ​ ​ ​}

Slide 10 - Quiz

Differentiëren - 5A

Items in this lesson

Slide 1 - Quiz

Slide 2 - Quiz

Slide 3 - Quiz

Slide 4 - Quiz

Slide 5 - Quiz

Slide 6 - Quiz

Slide 7 - Quiz

Slide 8 - Quiz

Slide 9 - Quiz

Slide 10 - Quiz

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