3E Economics par. 5.5

• Economie
• Middelbare school
• vwo
• Leerjaar 3

Hw.

5.12a> No, all customers pay the same price

5.12b> Q = -2 x 300 + 1.200 = 600

5.12c> Turnover = 600 x € 300 = € 180.000,-

5.13
How many people want to buy a ticket at € 200,- (1)
How many people want to buy a ticket at € 400,- (2)

1. 1> 400 2> 400
2. 1> 400 2> 800
3. 1> 800 2> 400
4. 1> 800 2> 800

Hw.

5.13a> a plane ticket is personal and has your name on it, so you cannot resell it

5.13bcd> Turnover business people = 400 x € 400 = € 160.000

Turnover elderly,schools = 400 x € 200 = € 80.000

5.13ef> Total turnover increased to € 240.000,- because of the price discrimination

3E Economics par. 5.5

An ICT company started of in 2019 and we have the following financial information:

 In 2019 turnover was € 300.000,- and costs were € 244.000,-. In 2019 they also bought 5 computers for their employees for € 12.000,- in total.

In 2020 turnover increased to € 320.000,-  and costs increased to 

€ 268.000,-. 

For 2021 they expect turnover to drop to € 270.000,- and the costs to still be € 268.000,-. In 2022 they will buy new computers for the employees

In 2019 turnover was € 300.000,- and costs were € 244.000,-. In 2019 they also bought 5 computers for their employees for € 12.000,- in total.
In 2020 turnover increased to € 320.000,- and costs increased to € 268.000,-.
For 2021 they expect turnover to drop to € 270.000,- and the costs to still be
€ 268.000,-. In 2022 they will buy new computers for the employees.
Highest profit in?

1. 2019
2. 2020
3. 2021

Assignment

We buy the computers in year 2019, but it's not fair to say that the € 12.000,- belongs entirely in 2019.

We need to spread the cost over the service life of the computers and that is 3 years.

So not € 12.000,- in 2019 and € 0,- in 2020 and 2021, but 

12.000 / 3 = € 4.000,- Depreciation costs in 2019,2020 and 2021

Assignment

Result 2019 = 300.000 - 244.000 - 4.000 = € 52.000,-

Result 2020 = 320.000 - 268.000 - 4.000 = € 48.000,-

Result 2021 = 270.000 = 268.000 - 4.000 = - € 2.000,-

Depreciation

Fixed assets decrease in value over the years

The costs of the fixed assets is spread over the years

                                                    Purchase value - Residual value

Depreciation per year = -------------------------------------

                                                   Service life

( Sometimes depreciation is a % of the purchase value or book value )

Depreciation

A machine is bought 1/1/2019 for € 90.000,-. The service life is expected to be 9 years and we expect to get € 18.000,- for the old machine when we sell it 1/1/2028.

What is the book value of the machine 31/12/2020?

A machine is bought 1/1/2019 for € 90.000,-. The service life is expected to be 9 years and we expect to get € 18.000,- for the old machine when we sell it 1/1/2028.
What is the book value of the machine 31/12/2020?

1. € 70.000,-
2. € 74.000,-
3. € 80.000,-
4. € 82.000,-

Assignment

Depreciation = ( 90.000 - 18.000 ) / 9 = 8.000

Book value = 90.000 - 2 x 8.000 = € 74.000,-

Hw.

Par. 5.5 assignments 8 and 11

Make 4 groups of 4 and 3 groups of 3 for project Dragons Den

Par. 5.5 assignment 8c

1. 5 x 13.500
2. 450.000 + 5 x 13.500
3. 450.000 - 5 x 13.500

Par. 5.5 assignment 11

1. ( 27.000 - 500 ) / 15
2. ( 27.000 + 500 ) / 15
3. ( 38.000 - 500 ) / 15
4. ( 38.000 + 500 ) / 15

Par. 5.2 assignment 4a

1. Gerard: 4 > 3
2. Frits: 7 > 4,50

Par. 5.2 assignment 4b

1. Gerard: 4,50 < 7
2. Frits: 7 > 4,50
3. Gerard: (4,50 / 4 < (7 / 3)
4. Frits: (7 / 3) > (4,50 / 4)

Par. 5.2 assignment 8a
Dutch international competitiveness will ...

1. Decrease
2. Increase

Par. 5.2 assignment 8b

1. 5 - 10
2. 10 - 5
3. 105 / 110
4. 110 / 105

Dragons Den