Quiz circuits, conversion and power

• physics
• Middelbare school
• vwo
• Leerjaar 2

Quiz Circuits, Conversion Power.

Series & Parallel circuits

What is the voltage
accross each bulb in this
circuit?

In a series circuit, the electrical energy from the source, the voltage, has to be divided equally when the bulbs are equal. Thus 12/3 = 4 V

1. 12V
2. 6V
3. 4V
4. 0V

What is the current at
position B?

1.5 A

B

In a series circuit, the current has no other way to go, rather than go through the entire circuit. Therefore, the current is the same in the entire circuit. 

1. 0.5A
2. 1.5A
3. 4.5A
4. 0A

What is the voltage accross
the middle bulb?

This is a parallel circuit. Every bulb is connected on one side to the positive side of the battery and on the other side to the negative side of the battery. The entire electrical energy is used across the bulb, thus the voltage across every bulb is 12V.

1. 12V
2. 6V
3. 4V
4. 0V

What is the current through
the bulb on the bottom?

6A

When all the lamps in a parallel circuit are the same, every branch in the parallel circuit carries the same amount of current through it. In this example, the 6A is divided in 3 branches with each 2 Amps of current through it. 

1. 6A
2. 3A
3. 1A
4. 2A

Conversion

Convert:
5 A = ..... mA

5 x 1000 = 5000 mA

Convert:
480 mA = ..... A

480 / 1000 = 0.48 A

Convert:
8.6 kV = ..... V

8.6 x 1000 = 8600 V

Convert:
200 mV = ..... kV

(200 / 1000) / 1000 = 0.0002

Convert:
0.1289 kA = ...... mA

0.1289 x 1000 x 1000 = 128900 mA

Power

P = U x I

Calculate the power of
Bulb 1.

12V

300mA

Bulb 1

I = 300 mA = 0.3 A

U = 12/2 = 6V (divided by 2 because of series circuit)

P = 6 x 0.3 = 1.8 W

1. 12W
2. 1,8W
3. 1800W
4. 3600W

Calculate the power of
Bulb 1.

12V

300mA

Bulb 1

In the circuit, the bulbs are connected parallelly. As the bulbs are the same, the current is divided over both bulbs. Therefore, the current through bulb 1 is also 300 mA. 

I = 300 mA = 0.3 A

U = 12 V

P = 12 x 0.3 = 3.6 W

1. 12W
2. 300W
3. 3,6W
4. 3600W

Mixed circuits

260mA

240mA

What are the voltages across bulb 1 till 5. Answer is as following: Bulb 1,Bulb2,Bulb3,etc.

1. 12V, 6V, 12V, 6V, 12V
2. 6V, 6V, 4V, 4V, 4V
3. 12V, 12V, 12V, 12V, 12V
4. 6V, 6V, 12V, 12V, 12V

What are the currents trough wire 6 till 9. Answer is as following: point 6, point 7, point 8, point 9

1. 20 mA, 80 mA, 240 mA, 260 mA
2. 240 mA, 240 mA, 240 mA, 260 mA
3. 10 mA, 80 mA, 80 mA, 100 mA.
4. 20 mA, 80 mA, 260 mA, 260 mA