Chapter 8.2

Chapter 8.2
1 / 17
volgende
Slide 1: Tekstslide

In deze les zitten 17 slides, met tekstslides.

Onderdelen in deze les

Chapter 8.2

Slide 1 - Tekstslide

Period 2
Sound

Slide 2 - Tekstslide

This lesson
  • Recap
  • Paragraph 8.2 — pitch and frequency
  •  Working independently

Slide 3 - Tekstslide

How is sound produced?
  • Through a vibration

What is sound made off?
  • Sound waves

How does sound travel over distance?
  • Through a medium

Slide 4 - Tekstslide

Pitch is a word we use to describe how high or low a sound is. For example:
– A whistle has a high pitch.
– A drum has a low pitch.

The pitch of the sound depends on in a string instrument:

1.Thickness: the thinner the string, the higher the pitch
                       the thicker the string, the lower the pitch

2.Length: the shorter the string, the higher the pitch

3.Tension: the tighter the string, the higher the pitch"

Slide 5 - Tekstslide

We can make sound visible. We do this with an oscilloscope.
With the oscilloscope you can analyze the sound.

Slide 6 - Tekstslide

The screen of the oscilloscope is divided into small squares. The time base tells you how much time one square represents.
For example: A time base of 500 ms/division means that one square shows 500 milliseconds."

Slide 7 - Tekstslide

The vibration period and frequency
Each square on the oscilloscope gives an amount of time called
Time base
time base  = 0,5 ms per 
division
And each vibration takes a certain
amount of time to complete




Slide 8 - Tekstslide

The vibration period and frequency
The vibration period is the amount of time it takes to complete 1 full vibration

In this picture we see multiple vibrations, at which point(s) do we see a completed vibration?

Slide 9 - Tekstslide

The vibration period and frequency
With the time 1 square takes up, and the amount of completed vibrations we can calculte the vibration period (T)

For example, we have 
3 completed vibrations

What is the time for these 3 vibrations?

Slide 10 - Tekstslide

The vibration period and frequency
We divide the time it takes to complete a certain amount of vibrations with the number of vibrations and we get the vibration period (T)
T = 2,4/3=0,8ms = 0,0008 s

So one full vibration = 0,0008 s

Slide 11 - Tekstslide

The vibration period and frequency
If we know the period of a vibration we can calculate its frequency (f) in Hertz (Hz)
We can use this the formula 
f = 1/T

If we know the frequency and want to 
Calculate vibration period: then you can 
Use T= 1/f




Slide 12 - Tekstslide

The vibration period and frequency
When we calculated T we got the answer of 0,8ms
Now we can calculate the frequency
f = 1/t

f=1/0,0008=1250Hz
Which means 1250 vibrations per second

Slide 13 - Tekstslide

The vibration period and frequency
We humans are able to hear sounds with low and high frequencies

Our hearing range is between 20hz and 20000hz


Slide 14 - Tekstslide

Slide 15 - Tekstslide

See the images below. total time is 8 milliseconds go by.


What is the frequency of this wave? use the formula 
f=T1

Slide 16 - Tekstslide

See the images below. you have 1 ms/div.


What is the frequency of this wave? use the formula 
f=T1
Given
T = 2 milliseconds = 0.002 seconds.

Asked
What is the frequency?

Formula



Calculation
f = 1/T = 1/0.002 =500 Hz
f=T1

Slide 17 - Tekstslide