# 1819 H2Y §6.Practice Test

Which exercises should we discuss on the board?
1 / 14
Slide 1: Woordweb
WiskundeMiddelbare schoolhavoLeerjaar 2

In deze les zitten 14 slides, met interactieve quiz en tekstslides.

Lesduur is: 50 min

## Onderdelen in deze les

Which exercises should we discuss on the board?

#### Slide 1 -Woordweb

Overview CH6
- You know what the short sides and what the hypotenuse is in a right-angled triangle.
- You can make sketches.
- You can use Pythagoras' theorem to calculate the third side in a right-angled triangle when you know two sides.
- You can give exact answers.
- You can use Pythagoras' theorem in stories and round your answer sensibly.
- You can use Pythagoras' theorem in cuboids and pyramids

(NOT §6.5, finding out if triangles are acute- or obtuse-angled)

#### Slide 2 -Tekstslide

Shorter sides & hypotenus
All right-angled triangles have 2 shorter sides and 1 hypotenuse.

The hypotenuse is the longest side and always lies opposite the right angle.
The shorter sides are (as the name suggests)
shorter than the hypotenus and always lie
on either side of the right angle.

#### Slide 3 -Tekstslide

Calculating unknown sides

Example

1) Sketch:

#### Slide 5 -Tekstslide

Example

2) Fill in known sides:

#### Slide 6 -Tekstslide

Example

3) Calculate the known squares

#### Slide 7 -Tekstslide

Example

4) Calculate the unknown square

81 - 49 = 32

#### Slide 8 -Tekstslide

Example

5) Calculate the unknown side

Example

BC=32

#### Slide 10 -Tekstslide

Pythagoras in solids
In the box on the right AB = 6, BC = 12
and AE = 6. Calculate BH

#### Slide 11 -Tekstslide

Pythagoras in solids
In the box on the right AB = 6, BC = 12
and AE = 6. Calculate BH

#### Slide 12 -Tekstslide

Pythagoras in solids
In the box on the right AB = 6, BC = 12
and AE = 6. Calculate BH

#### Slide 13 -Tekstslide

HW Monday
Make and correct:
- Practice Test CH 6 in your workbook (NOT 8)
- §6.6: 38, 39, 40, 41, 42 (NOT 43, 44)

You can work on this during class time on Friday