preparing for the formative assessment

Good Day! 
Schedule: 
  • Revise chapter 3 
  • Practise 
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Slide 1: Tekstslide
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In deze les zitten 32 slides, met interactieve quizzen en tekstslides.

time-iconLesduur is: 40 min

Onderdelen in deze les

Good Day! 
Schedule: 
  • Revise chapter 3 
  • Practise 

Slide 1 - Tekstslide

What paragraph do you find the most difficult?
3.1 The graph of a linear function
3.2 Finding the equation of a line
3.3 linear relationships
3.4 The balance method
3.5 Solving equations
3.6 Applying equations

Slide 2 - Poll

3.1 The graph of a linear function


How to draw a graph of a linear function in the coordinate plane
  1. Make a table with at least 2 points. 
  2. Plot these points in the coordinate plane. 
  3. Draw a line through these points. 
  4. Don't forget to write the formula next to your graph! 

Slide 3 - Tekstslide

Example
Draw the graph of y = -3x + 2. 
1. 

x
0
1
y
2
-1
For x = 0 
y = -3 · 0 + 2 = 0 + 2 = 2
y = 2
For x = 1
y = -3 · 1 + 2 = -3 + 2 = -1
y = -1
This gives us the points:  
(0,2) and (1,-1)

Slide 4 - Tekstslide

Example 
2. Plot (0,2) and (1,-1)

Slide 5 - Tekstslide

Example 
2. Plot (0,2) and (1,-1)
3. Draw a line through (0,2) and
(1,-1)

Slide 6 - Tekstslide

Example 
2. Plot (0,2) and (1,-1)
3. Draw a line through (0,2) and
(1,-1)
4. Write the formula next to the 
graph!!

Slide 7 - Tekstslide

3.1 The graph of a linear function 
How to check if a point is on a line
To check if point (x,y) in on a line you fill in the x-coordinate in the formula of the line and see if the answer matches the y-coordinate.

If the answer and the y-coordinate are the same, the point is on the line. 

Slide 8 - Tekstslide

Example
Calculate wether points A(9,15) and B(-2,-8) are on line y = 2x - 3
Check point A: 
Filling in x = 9 in y = 2x-3 gives: 
y = 2 · 9 - 3 = 18 - 3 = 15
Check point B:
Filling in x = -2 in y = 2x-3  gives:
y = 2 · -2 - 3 = -4 - 3 = -7  
Point A(9,15) is on the line
Point B(-2,-8) is not on the line

Slide 9 - Tekstslide

3.2 Finding the equation for a line

The formula for a linear relationship between x and y in an equation in the form 
y = ax+b

Going 1 to the right means going a up
The line has y-intercept (0,b)

Slide 10 - Tekstslide

y = 2x -3
Going 1 to the right means going 2 up
This line has y-intercept (0,-3)

Slide 11 - Tekstslide

how to find the equation of a line 
1. Assume y = ax + b 
2. Find the y-intercept. This is (0,b)
3. Pick two grid points on the line. 


4. Write down the equation. 

a=runrise

Slide 12 - Tekstslide

a = .....

Slide 13 - Open vraag

What is the
y-intercept?
A
(0,1)
B
(1,0)
C
(0,-1)
D
(-1,0)

Slide 14 - Quizvraag

What is the
equation of this line?
Answers from the previous questions:
a = -2 
y-intercept = (0,-1)

Slide 15 - Open vraag

Equations of parallel lines
Lines with the same gradient are parallel 
Parallel lines have the same gradient

Line l and k both have gradient -2
Line l and k are parallel

Line m has gradient 3
Line m is not parallel to line l or k

Slide 16 - Tekstslide

3.3 linear relationships 
How to find the equation of a line where the axis have different lables than x and y.

The horizontal axis is labelled p and the vertical axis is labelled N

The equation is in the form: 
N = ap + b



Slide 17 - Tekstslide

Find the equation

1. The equation is in the form 
N = ap + b 
2. The line goes through (0, -80), so b = -80 
3.                                        
4.  N = ap + b
b = -80 and a = 5 so 
N = 5p - 80       
a=runrise=20100=5

Slide 18 - Tekstslide

The sum graph 

To draw the sum graph of two graphs you need two points of this graph. 
You can find these points in two way:
1. By adding the y-values of the two graphs with the same x-value 
2. By finding the points directly above the x-intercepts of the two graphs
You don't need to know this for the test!

Slide 19 - Tekstslide

1. Adding y-values
Given are the lines f and g with equations f: y = -2x + 6 and
g: y = 3x - 2  


f. 


g. 


f + g.  


Two points on the sum graph are : 
(0,4) and (1,5)
x
0
1
y
6
4
x
0
1
y
-2
1
x
0
1
y
6 + -2
4 + 1
You don't need to know this for the test!

Slide 20 - Tekstslide

You see the sum graph of line f and g. In what order would you do these steps to find the sum graph?
You don't need to know this for the test!
Step 1: find the x-intercept 
Step 2:
 Find the y-values directly above the y-intercepts 
Step 3: Draw a line through the new points 

Slide 21 - Sleepvraag


1. substracting y-values
Given are the lines f and g with equations f: y = -2x + 6 and
g: y = 3x - 2  


f. 


g. 


f - g.  


Two points on the sum graph are : 
(0,8) and (1,3)
x
0
1
y
6
4
x
0
1
y
-2
1
x
0
1
y
6 - -2
4 - 1
The difference graph
You don't need to know this for the test!

Slide 22 - Tekstslide

1. finding the y-values with the x-intercepts

Step 1: Find the x-intercept with the same y-value as the intersection point

Step 2: Find the x-intercept of the line you are substracting


Step 3: Find the point with the same x-value as the point you found in step 2 on the other line (in this case line f)

Step 4: Draw a line through the two points from step 1 and step 3 
In this case we are trying to find lin f-g
So we are looking for the x-intercept of line g
You don't need to know this for the test!

Slide 23 - Tekstslide



When you have an equation and you want to find the solution for x:

You can Add or Substract the same number on both sides
You can multiply or divide by the same number on both sides

Example: 

5x + 7      = 32
         -7          -7
5x + 7 -7 = 32 -7
5x + 0      = 25
5x              = 25 
:5                   :5
5x:          = 25:5
x                  = 5
3.4 The balance method
We always want the variables on the lefthand side, 
That's why we try to remove the 7 from the LHS first

Slide 24 - Tekstslide

Try it yourself! 

1. -7x + 3 = 24                                                       2. -5 + 6x = 37

Try to remove the 3 on the left hand side first. 
We only want x on the left hand side!
Hint
Try to remove the -5 on the left hand side first. 
We only want x on the left hand side!
Hint

Slide 25 - Tekstslide

Solutions 
1. -7x + 3        = 24                                             2. -5 + 6x         = 37 
            - 3     - 3                                                        +5              +5
    -7x + 3 - 3 = 24 - 3                                            -5 + 5 + 6x = 37 + 5
    -7x + 0       = 21                                                    0 + 6x           =  42 
    -7x               = 21                                                    6x                  = 42
     :-7                     :-7                                                 :6                        :6
    -7x : -7          = 21:-7                                             6x : 6            = 42 : 6 
     x                     = -3                                                   x                    = 7
    


Slide 26 - Tekstslide

3.5 Solving equations
In what order should you solve an equation (with brackets)? 
1. 
2. 
3. 
4. 
If there are brackets, multiply them out. 

Simplify the LHS and the RHS if needed.

Move all the terms with a variabel to the LHS and move all the terms without a variabel to the RHS.
Divide by the number in front of the variabel

Slide 27 - Sleepvraag

3.5 Solving equations 
Equations with fractions 
When you want to change a fraction into a whole number, you multiply the fraction by it's denominator because: 

so what should
we do when      
4314=412=3
53x=6
4/1 = 4 
?

Slide 28 - Tekstslide

How would you solve
?
53x=6

Slide 29 - Open vraag

3.6 Applying equations 
You can solve many problems using an equation!! 


Problem: 

In 4 years I will be 5 times as old as I was 16 years ago. How old am i now? 
I want to know my age right now so we will call this x. Right now I am x years old.

How old am I in 4 years? 
How old was I 16 years ago?  
What is equal to my age 16 years ago times 5?



Slide 30 - Tekstslide

3.6 Applying equations 
You can solve many problems using an equation!! 


Problem: 

In 4 years I will be 5 times as old as I was 16 years ago. How old am i now? 
Right now my age is x
How old am I in 4 years? x + 4
How old was I 16 years ago?  x - 16
What is equal to my age 16 years ago times 5? (x - 16) · 5 = x + 4

Now solve for x to find my age! 





Slide 31 - Tekstslide

What can I work on right now? 
Mixed exercises: p. 122-123

Diagnostic test: p.126-127

Revision: p. 128-129

Slide 32 - Tekstslide